Question

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Answer 1

1.)3x-2y=9, for y
3x=9+2y
3x-9=2y
(3x-9)/2=y
(3/2)x-(9/2)=y
2.) I=prt, for r
I=(p*t)*r
I/(p*t)=r
3.)S=2(pi)rh, for h
S=(2*(pi)*r)*h
S/(2*(pi)*r)=h

Answer 2

3x - 2y = 9...subtract 3x from both sides
-2y = -3x + 9...divide by -2 on both sides
y = 3/2x - 9/2 <=
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I = PRT...divide both sides by PT
I / PT = R
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S = 2(pi)RH ...divide both sides by 2(pi) R
S / (2(pi)R) = H