Answer: 0.8413
Step-by-step explanation:
Given : Henry has collected data to find that the typing speeds for the students in a typing class has a normal distribution.
Mean : [tex]\mu=47[/tex]
Standard deviation : [tex]\sigma= 4[/tex]
Let x be the random variable that represents the typing speeds for the students.
The z-score :-
[tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x= 51
[tex]z=\dfrac{51-47}{4}=1[/tex]
Using the standard normal distribution table ,the probability that a randomly selected student has a typing speed of less than 51 words per minute :-
[tex]P(x<51)=P(z<1)\\\\= 0.8413447\approx 0.8413[/tex]
Hence, the probability that a randomly selected student has a typing speed of less than 51 words per minute = 0.8413