Answer:
Average acceleration is [tex](11.05)g\ m/s^2[/tex]
Explanation:
It is given that,
Initial velocity, u = 0
Final velocity, v = 6.5 km/s = 6500 m/s
Time taken, t = 60 s
Acceleration, [tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{v}{t}[/tex]
[tex]a=\dfrac{6500\ m/s}{60}[/tex]
[tex]a=108.33\ m/s^2[/tex]
Since, [tex]g=9.8\ m/s^2[/tex]
So, [tex]a=(11.05)g\ m/s^2[/tex]
So, the angular acceleration of the missile is [tex](11.05)g\ m/s^2[/tex]. Hence, this is the required solution.