Tom travels between the two mile markers shown and then finds his average speed in miles per hour. Select the three equations that represent this situation.
![Tom travels between the two mile markers shown and then finds his average speed in miles per hour Select the three equations that represent this situation class=](https://us-static.z-dn.net/files/d29/29a2b1392587d9a96506ce71909e5d53.png)
Speed is the rate of distance over time.
The equations are:
The given parameters are:
[tex]\mathbf{(t_1,d_1) = (1:30pm,35miles)}[/tex]
[tex]\mathbf{(t_2,d_2) = (4:30pm,230miles)}[/tex]
So, the time difference is:
[tex]\mathbf{t=4:30pm - 1:30pm}[/tex]
[tex]\mathbf{t=3\ hours}[/tex]
The distance traveled is:
[tex]\mathbf{d = 230miles - 35miles}[/tex]
[tex]\mathbf{d = 195miles}[/tex]
Speed is calculated as:
[tex]\mathbf{Speed = \frac{Distance}{Time}}[/tex]
So, we have:
[tex]\mathbf{Speed = \frac{195\ miles}{3\ hours}}[/tex]
Multiply both sides by 3 hours
[tex]\mathbf{3\ hours \times Speed = 195\ miles}[/tex]
Divide both sides by Speed
[tex]\mathbf{3\ hours = \frac{195\ miles}{Speed}}[/tex]
Hence, the equations are:
[tex]\mathbf{Speed = \frac{195\ miles}{3\ hours}}[/tex]
[tex]\mathbf{3\ hours \times Speed = 195\ miles}[/tex]
[tex]\mathbf{3\ hours = \frac{195\ miles}{Speed}}[/tex]
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