Answer:
Step-by-step explanation:
The point-slope of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-2, 0) and (2, 8).
Substitute:
[tex]m=\dfrac{8-0}{2-(-2)}=\dfrac{8}{4}=2[/tex]
for the point (-2, 0):
[tex]y-0=2(x-(-2))\\\\y-0=2(x+2)[/tex]
for the point (2, 8):
[tex]y-8=2(x-2)[/tex]