Answer:
0.6672 kg/s
Explanation:
Q = Volume of air = 2000 m³/h = 2000/3600 =0.556 m³/s
Length of duct = 1000 mm = 1 m
Breadth of duct = 500 mm = 0.5 m
ρ = Density of air = 1.2 kg/m³
A = Cross-sectional area = 1×0.5 = 0.5 m²
V = Average air velocity
a) Q = AV
⇒V = Q/A
⇒V = 0.556/0.5 = 1.112 m/s
b) Mass flow rate = ρ×A×V
⇒Mass flow rate = 1.2×0.5×1.112
∴ Mass flow rate is 0.6672 kg/s