Respuesta :

It’s wrong because it isn’t one of the zeroes for the equation
f(x)=-16x^2+64x+80
Divide by -16
x^2-4x-5
(x-5)(x+1)
Set them up to zero
x-5=0. x+1=0
x=5. x=-1
5 and -1 are your possible zeroes
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