Answer:
F = 3.98 kN
Explanation:
GIVEN DATA:
sides of box = 17 cm
pressure = 1 atm = 101325 N/m2
T2 = 378K
T1 = 278 K
final pressure can be calculate by using below relation
[tex]\frac{P_{1}}{P_{2}}=\frac{T_{1}}{T_{2}}[/tex]
we know that
force = pressure * area
therefore force is
[tex]F =(\frac{T_{1}}{T_{2}}*P_{1})A[/tex]
[tex]F =(\frac{378}{278}*101325)(17*10^{-2})^{2}[/tex]
F = 3.98 kN