Question

The length of a rectangle is three times its width.
If the perimeter of the rectangle is 40 in, find its area.

Answer 1

Answer:

75 in^2

Step-by-step explanation:

L = 3W here.  Also, P = 2W + 2L = 40 in here.  Subbing 3W for L, we get

                                    2W + 2(3W) = 40, or

                                     2W + 6W = 40, or 8W = 40.  Thus, W = 5 in and L = 15 in

and the area is W*L, or 5(15) in^2, or 75 in^2