Question

Determine the value of g(4), g(3 / 2), g (2c) and g(c+3) then simplify as much as possible.

g(r) = 2 $\pi$ r h

Answer 1

Answer:

$g(4) = 8 \pi h\\\\g(\frac{3}{2}) = 3 \pi h\\\\ g(2c) = 4 \pi ch\\\\g(c+3) = 2 \pi hc+6\pi h$

Step-by-step explanation:

You need to substitute $r=4$ into $g(r) = 2 \pi r h$. Then:

$g(4) = 2 \pi(4)h\\\\g(4) = 8 \pi h$

Substitute $r=\frac{3}{2}$ into $g(r) = 2 \pi r h$. Then:

$g(\frac{3}{2}) = 2 \pi(\frac{3}{2})h\\\\g(\frac{3}{2}) = 3 \pi h$

Substitute $r=2c$ into $g(r) = 2 \pi r h$. Then:

$g(2c) = 2 \pi(2c))h\\\\g(2c) = 4 \pi ch$

Substitute $r=c+3$ into $g(r) = 2 \pi r h$. Then:

$g(c+3) = 2 \pi (c+3)h\\\\g(c+3) = 2 \pi hc+6\pi h$

Answer 2

For this case we have the following function:

$g (r) = 2 \pi * r * h$

We must evaluate the function for different values:

$g (4) = 2 \pi * (4) * h = 8 \pi*h\\g (\frac {3} {2}) = 2 \pi * (\frac {3} {2}) * h = 3 \pi*h\\g (2c) = 2 \pi * (2c) * h = 4 \pi * c * h\\g (c + 3) = 2 \pi * (c + 3) * h = 2 \pi * c * h + 6 \pi * h$

Answer:

$g (4) = 8 \pi*h\\g (\frac {3} {2}) =3 \pi*h\\g (2c) = 4 \pi * c * h\\g (c + 3) = 2 \pi * c * h + 6 \pi * h$