Question

Consider a generator that rotates its 200 turn, 0.18 m diameter coil at 3250 rpm in a 0.65 T field. Calculate the peak voltage of the generator.

Answer 1

Answer:

1124.8 Volt

Explanation:

N = 200, Diameter = 0.18 m, Radius, r = 0.09 m, f = 3250 rpm = 54.17 rps

B = 0.65 T

the peak value of induced emf is given by

e0 = N x B x A x ω

e0 = 200 x 0.65 x 3.14 x 0.09 x 0.09 x 2 x 3.14 x 54.17

e0 = 1124.8 Volt