Respuesta :
Answer:
because reference table I shows that delta h for one mole of c2h6(g) is 84.0 kj so for 2 moles of c2h6(g) is 168.0kj
168 kJ/mol is the net amount of heat released when two moles of C₂H₆ are formed from its elements at 101.3 kpa and 298 K.
What is Enthalpy of formation ?
The standard reaction enthalpy for formation of the compound from the atoms or molecules at stable states that is temperature 298 K and Pressure 1 bar is called as enthalpy of formation.
What is the enthalpy of ethane ?
1 Atm (Atmospheric pressure) = 101.3 KPa (Kilopascal)
At 1 atm and 298 K the enthalpy of formation of ethane is -84 kJ/mol.
The enthalpy of formation of 1 mole of C₂H₆ is 84 kJ/mol because heat is released here so enthalpy of formation is positive.
Therefore, the enthalpy of formation of 2 mole of C₂H₆ = 2 × 84 kJ/mol
= 168 kJ/mol
Thus from the above conclusion we can say that 168 kJ/mol is the net amount of heat released when two moles of C₂H₆ are formed from its elements at 101.3 kpa and 298 K.
Learn more about the Enthalpy of formation here: https://brainly.com/question/14047927
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