Keith determines the zeros of the function f(x) to be -6 and 5.
What could be Keith’s function?
(1) f(x) = (x + 5)(x + 6) (3) f(x) = (x - 5)(x + 6)
(2) f(x) = (x + 5)(x - 6) (4) f(x) = (x - 5)(x - 6)

Respuesta :

the answer is 2 because -6 and +5 are only in that equation

These are equations that has a leading degree of 2. The function that keith generate is f(x) = (x+6)(x-5)

Quadratic equations

These are equations that has a leading degree of 2.  If the factors of a function is a and b, the equivalent function will be (x - a)(x -b)

Given the zeros of the function f(x) to be -6 and 5, the function is given as:

f(x) = (x -(-6)) (x - 5)\

f(x) = (x+6)(x-5)

Hence the function that keith generate is f(x) = (x+6)(x-5)

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