Question

What is the area of the irregular polygon shown below?

Answer 1

Answer:

D. 49 sq. units

Step-by-step explanation:

Find the area of the triangle up top first then multiply it by 4 to get the area of the rhombus up top:

4 x 3 = 12  

12/2 = 6

6 x 4 = 24

now solve the lower square:

5 x 5 = 25

now add the two together:

25 + 24 = 49

Answer 2

Answer:

Correct option is:

D. 49 sq. units

Step-by-step explanation:

The irregular polygon shown is the combination of rhombus and square

The lower part of the polygon is square with side 5 units

and the upper part of the polygon with rhombus with diagonal (4+4)=8 and (3+3)=6 units

Area of irregular polygon=Area of square+Area of rhombus

                                         = side²+Product of diagonals/2

                                         = 5²+(8×6)/2  sq. units

                                         = (25+24) sq. units

                                         = 49 sq. units

Hence, Correct option is:

D. 49 sq. units