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A car is travelling down a highway away from its starting location with a distance function with d(t) = 8(t? – 6t2 +12t) where t is in hours and d is in kilometres.

a. What is the average velocity over [1, 3]?
(5 marks]​

Respuesta :

The average velocity is the rate of the distance function over time

The average velocity over the interval [1, 3] is 8 kilometers per hour

How to determine the average velocity?

The distance function is given as:

d(t) = 8(t³ - 6t² + 12t)

The interval is given as: [1,3]

Calculate d(1) and d(3)

d(3) = 8(3³ - 6 * 3² + 12 * 3)

Evaluate

d(3) = 72

d(1) = 8(1³ - 6 * 1² + 12 * 1)

Evaluate

d(1) = 56

The average velocity (v) is the calculated as:

v = (d(3) - d(1))/(3 - 1)

Substitute known values

v = (72 - 56)/(3 - 1)

Evaluate

v = 8

Hence, the average velocity over [1, 3] is 8 kilometers per hour

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