Question

nPr if n = 8 and r = 5

Answer 1

For this case we have that by definition, the formula to count the total number of different permutations is:

$nP_ {r} = \frac {n!} {(n-r)!}$

SUstituyendo:

$n = 8\\r = 5$

We have:

$8P_ {5} = \frac {8!} {(8-5)!} = \frac {8!} {3!} = \frac {8 * 7 * 6 * 5 * 4 * 3!} {3! } = 6720$

ANswer:

$8P_ {5} = 6720$