The linear equation that passes through the two given points is:
y = (1/3)*x + (5/3)
How to find the linear equation?
A linear equation is written as:
y = a*x + b
Where a is the slope and b is the y-intercept.
If a line passes through two points (x₁, y₁) and (x₂, y₂), then the slope is equal to:
a = (y₂ - y₁)/(x₂ - x₁).
In this case, we know that the line passes through (-2, 1), and (4, 3).
Then the slope is:
a = (3 - 1)/(4 - (-2)) = 2/6 = 1/3
So the line is something like:
y = (1/3)*x + b
To find the value of b, we use the fact that the line passes through the point (4, 3), then:
3 = (1/3)*4 + b
3 - 4/3 = b
5/3 = b
So the line is:
y = (1/3)*x + 5/3
Finally, the x-intercept of the line is the value of x such that y = 0.
0 = (1/3)*x + 5/3
-5/3/(1/3) = x = -5
The graph of the line can be seen below.
If you want to learn more about linear equations, you can read:
https://brainly.com/question/1884491
