Question

Red, blue, yellow, and green marbles are in a bag, with 14 marbles of each color. One white marble is added to the bag for a total of 57 marbles. What is the probability of choosing the white marble or a yellow marble from the bag?

Answer 1

Answer:

$\dfrac{15}{57}$ or 0.2632 or 26.32%

Step-by-step explanation:

Choosing a white or a yellow marble from the bag are two mutually exclusive events. So we can say that:

$P(W or Y) = P(W) + P(Y)$

To get the probability of each we divide the favorable outcomes by the all possible outcomes.

Probability of choosing white:

$P(W) = \dfrac{1}{57}$

Probability of choosing yellow:

$P(W)=\dfrac{14}{57}$

$P(WorY)=P(W)+P(Y)$

$P(WorY)=\dfrac{1}{57}+\dfrac{14}{57}$

$P(WorY)=\dfrac{15}{57}$

If you need it in decimal, just divide and you will get 0.2632.

If you need it in percent, just multiply the decimal by 100% and you will get 26.32%.

Answer 2

Answer:

15/57

Step-by-step explanation:

Given  

Total sample space=57 (as one marble was also added to the bag)

Now,

Let P(A)  be the probability of drawing a white marble

Let P(B) be the probability of drawing a yellow marble

So,

P(A)=1/57

P(B)=14/57

As we have to calculate the probability of white or yellow marble

P(A or B)=P(A)+P(B)

=1/57+14/57

=(1+14)/57

=15/57

So the probability of drawing a white or yellow marble is 15/57 ..