Question

1. A person preparing medicine wants to convert 15% alcohol solution into 32% alcohol
solution. Find how much pure alcohol should he mix with 400 mL of 15% alcohol
solution to obtain it.

Pls give me an answer to this. I will give 10 points.​

Answer 1

Answer: 100mL

Step-by-step explanation:

A 15% alcohol solution contains 15mL alcohol in 100mL solution

In 400ml there will be 400mL·15/100 = 6,000mL/100 = 60mL alcohol

Let the volume of pure alcohol to be added V.

In the new solution there will be (60 + V)mL  alcohol

And the total volume will be (400 + V)mL

Concentration required 32% = 0.32

Concentration = (60 + V)mL/(400 + V)mL = 0.32

60mL + VmL = 0.32(400 + V)mL

60mL + VmL = 128mL + V·*0.32mL

VmL - V·0.32mL = 128mL - 60mL = 68mL

V(1 - 0.32)mL = 68mL

V·0.68mL = 68mL

VmL = 68mL/0.68 = 100mL ►  alcohol volume to be added

Answer : 100mL

Verification

New solution

There will be  400mL + 100mL = 500mL total volume

There will be 60mL alcohol + 100mL alcohol = 160mL alcohol

The concentration will be   160mL/500mL = 0.32 = 32%

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