Question

The quadratic formula gives which roots for the equation 2x^2+7x=-2

Answer 1

answer: x= -(7+√33)/4 , x=-(7-√33)/4

Answer 2

The roots of the given equation should be  $x= -(7+\sqrt 33)\div 4 , x=-(7-\sqrt 33)\div 4$

Given information:

The equation is $2x^2+7x=-2$

Calculation of roots:

$2x^2 + 7x + 2 = 0\\\\x = [-7 \pm \sqrt (7^2 - 4\times 2\times 2)] \div 2\times 2\\\\x = -7\div 4 \pm \sqrt (33) \div 4\\\\= (-7 \pm \sqrt33) \div 4$

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