Respuesta :
Answer:
Female gametes AB, male gametes ab
Offspring-heterozygous genotype AaBb
Explanation:
If we name the gene for the body color with A and gene for the eye color with B and if the brown body is dominan over ebony body, while red eyes are dominant over sepia eyes, than the genotypes of the parents would be: female- AABB, male-aabb
P: AABB x aabb
Female gametes AB, male gametes ab
F1: AaBb all of the offspring would be heterozygous.
Genes for eye and body color are autosomal, not linked, with no interaction, and expressing complete dominance. Female Genotype SSEE / Gametes: SE, SE, SE, SE. Male Genotype ssee / Gametes: se, se, se, se.
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Available data:
- female flies ⇒h0m0zyg0us for brown bodies and red eyes
- male flies ⇒ h0m0zyg0us for ebony bodies and sepia eyes
We will assume autosomal genes, not linked, with no interaction, and complete dominance.
→ Autosomal genes
Gene for eyes color
- The dominant allele expresses red color, S
- Recessive allele expresses sepia color, s
Gene for body color
- The dominant allele expresses brown color, E
- Recessive allele expresses ebony color, e
→ Not linked
They assort independently from each other.
→ Complete dominance
When the dominant allele completely masks the recessive allele, we talk about complete dominance.
This is the case of individuals that are heter0zyg0us for a particular gene and express the dominant phenotype.
The dominant allele is hiding the expression of the recessive allele. Many genes show complete dominance.
→ No interaction
The presence of one of the genes, in either their dominant or recessive forms, does not affects the expression of the other gene.
Now, let us analyze the problem
Cross) female x male
Parentals) SSEE x ssee
Gametes) SE, SE, SE, SE se, se, se, se
F1) 100% heter0zyg0us for both traits, SsEe .
100% of the progeny will express red eyes and brown bodies.
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