Question

Find the common difference for the given sequence. 1.05, 1.1, 1.15, 1.2, ... 0.005 0.05 0.5

Answer 1

Given a sequence; a₁,a₂,a₃...,an,
The common difference is d= a₂-a₁=a₃-a₂=a₄-a₃....

In this case: 
a₁=1.05
a₂=1.1

d=a₂-a₁=(1.1)-(1.05)=0.05

Answer: The common difference is 0.05. 

Answer 2

Answer: 0.05

Step-by-step explanation:

In the given sequence, the first term = 1.05

The second term = 1.1

The difference between first and second term =$1.1-1.05=0.05$

The third term = 1.15

The difference between second and third term =$1.15-1.1=0.05$

The fourth term = 1.2

The difference between third and fourth term =$1.15-1.1=0.05$

Hence, the common difference of the given sequence =0.05