Respuesta :
Answer:
The value of most expensive car he can afford is $ 22913.757.
Step-by-step explanation:
Since, the periodic payment of a loan is,
[tex]P=\frac{r(PV)}{1-(1+r)^{-n}}[/tex]
Where, P.V. is the presents value of the loan,
r is the rate per period,
n is the number of periods,
Here, Monthly payment, P = $ 330,
⇒ The loan is compound monthly,
Thus, if the time = 6 years,
The number of periods, n = 6 × 12 = 72 months, ( 1 year = 12 months ),
Also, the A.P.R = 1.2 % = 0.012
So, the rate per periods,
[tex]r=\frac{0.012}{12}[/tex]
By substituting the values,
[tex]330=\frac{\frac{0.012}{12}(PV)}{1-(1+\frac{0.012}{12})^{-72}}[/tex]
[tex]\implies x = $ 22913.757[/tex]
Hence, the value of most expensive car he can afford is $ 22913.757.