Question

Find the limit of the function by using direct substitution. limit as x approaches one of quantity x squared plus three x minus one.

Answer 1

Answer:

Limit = -1

Step-by-step explanation:

We are given the following function:

$x^2 + 3x -1$

We are to calculate the limit of this function as x approaches zero.

For that, we will use direct substitution method and substitute the x with 0 in the given function to calculate its limit as follows:

$x ^ 2 + 3 x - 1$

$( 0 ) ^ 2 + 3 ( 0 ) - 1 = - 1$

Therefore, the limit is -1.

Answer 2

Answer:

limit is 3

Step-by-step explanation:

If we are trying to find:

lim→1

(x^2+3x-1)

This is actually really easy. When it states direct substitution, simply take our x limit and apply to the equation:

(x^2+3x-1)

(1^2+3(1)-1)

(1+3-1)=3

Therefore, our limit is 3!