Answer:
The surface area of the prism is [tex]1,664\ mm^{2}[/tex]
Step-by-step explanation:
we know that
The surface area of the triangular prism is equal to
[tex]SA=2B+PL[/tex]
where
B is the area of the triangular face
P is the perimeter of the triangular face
L is the length of the triangular prism
Find the area of the triangular face B
[tex]B=\frac{1}{2}(24)(16)= 192\ mm^{2}[/tex]
Find the perimeter of the triangular face P
[tex]P=(24+20+20)= 64\ mm[/tex]
we have
[tex]L=20\ mm[/tex]
substitute the values
[tex]SA=2(192)+(64)(20)=1,664\ mm^{2}[/tex]