Question

In the spin cycle of a washing machine, the tub of radius 0.299 m develops a speed of 652 rpm. What is the maximum linear speed with which water leaves the machine? Answer in units of m/s.

Answer 1

Answer:

Maximum speed of water that leaves the machine is 20.5 m/s

Explanation:

As we know that the angular frequency of the tub is

f = 652 rpm

so we have

$f = 10.87 rounds/sec$

now we have

$\omega = 2\pi f$

$\omega = 68.3 rad/s$

Now tangential speed is given as

$v = R\omega$

so we will have

$v = (0.299)(68.3)$

$v = 20.5 m/s$