Answer:
Lesser
Explanation:
The gravitational pull between a planet orbiting the Sun and the Sun is equal to the centripetal force keeping the planet in circular motion:
[tex]G\frac{mM}{r^2}=m\frac{v^2}{r}[/tex]
where
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}[/tex] is the gravitational constant
[tex]M[/tex] is the mass of the Sun
[tex]m[/tex] is the mass of the planet
[tex]r[/tex] is the distance between the Sun and the planet
v is the orbital velocity of the planet
We can re-arrange the formula to solve for v, the orbital velocity of the planet:
[tex]v=\sqrt{\frac{GM}{r}}[/tex]
We see that the velocity is inversely proportional to the square root of the distance, r: therefore, the farther the planet from the Sun, the lesser the orbital velocity of the planet.