Question

An artillery shell is fired at an angle of 26.3 ⦠above the horizontal ground with an initial speed of 1770 m/s. the acceleration of gravity is 9.8 m/s 2 . find the total time of flight of the shell, neglecting air resistance. answer in units of min.

Answer 1

t = 2*V₀*sin (α) / g
t = 2*1770*sin (26.3°) / 9.8 ≈ 2*1770*0.443 / 9.8 ≈ 160 s    or 2.7 min