Solve the missing elements for each problem. Use 3.14 for Pi
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Answer:
Radius is half of diameter, so just divide those by 2. And to find diameter, multiply by 2. Use the radius to find the circumference and the area.
Circumference=2πr Area=πr2
Step-by-step explanation:
The radius of a circle is half the diameter of the same circle.
Circle 1
The diameter is 38 inches.
This means that the radius is 19 inches
The circumference is calculated as:
[tex]C = 2\pi r[/tex]
So, we have:
[tex]C = 2 * 3.14 * 19[/tex]
[tex]C = 119.32[/tex]
The area is:
[tex]A= \pi r^2[/tex]
So, we have:
[tex]A= 3.14 * 19^2[/tex]
[tex]A= 1133.54[/tex]
Hence, the missing elements are:
Radius = 19 inches, Circumference = 119.32 inches and Area = 1133.54 square inches
Circle 2
The diameter is 32 inches.
This means that the radius is 16 inches
The circumference is calculated as:
[tex]C = 2\pi r[/tex]
So, we have:
[tex]C = 2 * 3.14 * 16[/tex]
[tex]C = 100.48[/tex]
The area is:
[tex]A= \pi r^2[/tex]
So, we have:
[tex]A= 3.14 * 16^2[/tex]
[tex]A= 803.84[/tex]
Hence, the missing elements are:
Radius = 16 inches, Circumference = 100.48 inches and Area = 803.84 square inches
Circle 3
The radius is 15 inches.
This means that the diameter is 30 inches
The circumference is calculated as:
[tex]C = 2\pi r[/tex]
So, we have:
[tex]C = 2 * 3.14 * 15[/tex]
[tex]C = 94.2[/tex]
The area is:
[tex]A= \pi r^2[/tex]
So, we have:
[tex]A= 3.14 * 15^2[/tex]
[tex]A= 706.5[/tex]
Hence, the missing elements are:
Diameter = 30 inches, Circumference = 94.2 inches and Area = 706.5 square inches
Circle 4
The diameter is 8 inches.
This means that the radius is 4 inches
The circumference is calculated as:
[tex]C = 2\pi r[/tex]
So, we have:
[tex]C = 2 * 3.14 * 4[/tex]
[tex]C = 25.12[/tex]
The area is:
[tex]A= \pi r^2[/tex]
So, we have:
[tex]A= 3.14 * 4^2[/tex]
[tex]A= 50.24[/tex]
Hence, the missing elements are:
Radius = 4 inches, Circumference = 25.12 inches and Area = 50.24 square inches
Circle 5
The radius is 18 inches.
This means that the diameter is 36 inches
The circumference is calculated as:
[tex]C = 2\pi r[/tex]
So, we have:
[tex]C = 2 * 3.14 * 18[/tex]
[tex]C = 113.04[/tex]
The area is:
[tex]A= \pi r^2[/tex]
So, we have:
[tex]A= 3.14 * 18^2[/tex]
[tex]A= 1017.36[/tex]
Hence, the missing elements are:
Diameter = 36 inches, Circumference = 113.04 inches and Area = 706.5 square inches
Circle 6
The diameter is 16 inches.
This means that the radius is 8 inches
The circumference is calculated as:
[tex]C = 2\pi r[/tex]
So, we have:
[tex]C = 2 * 3.14 * 8[/tex]
[tex]C = 50.24[/tex]
The area is:
[tex]A= \pi r^2[/tex]
So, we have:
[tex]A= 3.14 * 8^2[/tex]
[tex]A= 200.96[/tex]
Hence, the missing elements are:
Radius = 8 inches, Circumference = 50.24 inches and Area = 200.96 square inches
Circle 7
The diameter is 12 inches.
This means that the radius is 6 inches
The circumference is calculated as:
[tex]C = 2\pi r[/tex]
So, we have:
[tex]C = 2 * 3.14 * 6[/tex]
[tex]C = 37.68[/tex]
The area is:
[tex]A= \pi r^2[/tex]
So, we have:
[tex]A= 3.14 * 6^2[/tex]
[tex]A= 113.04[/tex]
Hence, the missing elements are:
Radius = 6 inches, Circumference = 37.68 inches and Area = 113.04 square inches
Circle 8
The radius is 10 inches.
This means that the diameter is 20 inches
The circumference is calculated as:
[tex]C = 2\pi r[/tex]
So, we have:
[tex]C = 2 * 3.14 * 10[/tex]
[tex]C = 62.8[/tex]
The area is:
[tex]A= \pi r^2[/tex]
So, we have:
[tex]A= 3.14 * 10^2[/tex]
[tex]A= 314[/tex]
Hence, the missing elements are:
Diameter = 20 inches, Circumference = 62.8 inches and Area = 314 square inches
Circle 9
The radius is 17 inches.
This means that the diameter is 34 inches
The circumference is calculated as:
[tex]C = 2\pi r[/tex]
So, we have:
[tex]C = 2 * 3.14 * 17[/tex]
[tex]C = 106.76[/tex]
The area is:
[tex]A= \pi r^2[/tex]
So, we have:
[tex]A= 3.14 * 17^2[/tex]
[tex]A= 907.46[/tex]
Hence, the missing elements are:
Diameter = 34 inches, Circumference = 106.76 inches and Area = 907.46 square inches
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