Match the function with the graph
![Match the function with the graph class=](https://us-static.z-dn.net/files/d5b/4dc50ff65c079b75523e8556c02d567b.png)
Answer:
Option: a is correct
a) y= -cos x
Step-by-step explanation:
We could clearly see that the graph of the function passes through a point on the y-axis which is :
(0,-1)
i.e. when x=0 the value of the function y= -1
So we will check in each of the following options by putting x=0 and check whether y= -1 or not.
b)
y=sin x
on putting x=0 we get:
y=sin 0=0≠ -1.
Hence, option b is incorrect.
c)
y= cos x.
we put x=0
y= cos 0=1≠ -1.
Hence, option c) is incorrect.
d)
y= -sin x
we put x=0 to obtain:
y= -sin 0=0≠ -1.
Hence, option d is incorrect.
Hence we are left with option a i.e.
The graph represents the function:
y= -cos x. (Hence, option a is correct)
( Also it satisfies at x=0
since, y= -cos 0= -1 )
Answer:
Choice A is the correct answer
Step-by-step explanation:
First things first, the function has a y-axis symmetry and is thus an even function. Choice B and D are automatically incorrect since the sine function is always odd. I employed Desmos graphing tool to plot the two remaining functions, and choice A matched the given graph