Question

Last year 640 cars and 160 pickups were sold at a car lot. This year the number of cars sold increased by 10%. In the same period, the number of pickups sold decreased buy 10%. What is the percent of increase of sales at the car lot?

Answer 1

See attachment for answer.

Answer 2

Answer:

5.66% is the increase of sales at the car lot.

Step-by-step explanation:

Last year a car lot consist of 640 cars and 160 pickups.

This year there is a increase of 10% in cars

Therefore number of cars increased this year = 640×10% = $(640)\frac{10}{100}=64$

So total cars sold = 640+64 = 704

Percentage dip in sales of pickups this year is 10%, therefore number of pickups decreased this year = 160×10% =$(160)\frac{10}{100} = 16$

So total pickups sold = 160-16 = 144

Total number of cars and pickups sold = 744+104 = 848

Now the percentage increase in number of cars = increase in lot×100/Lot size

= $\frac{48}{848}(100)=5.66%$