Question

Kiran has 2 3/4 pounds of flour. When he divides the flower into equal sized bags, he fills 4 1/8 bags. How many pounds fit in each bag? Write a multiplication problem and then answer the question.

Answer 1

Answer:  The required number of pounds of floor that fits in each bag is $\dfrac{2}{3}.$

Step-by-step explanation:  Given that Kiran has $2\dfrac{3}{4}$ pounds of flour. When he divides the flower into equal sized bags, he fills $4\dfrac{1}{8}$ bags.

We are to find the number of pounds that fit in each bag.

We will be using the UNITARY method to solve the problem.

We have

$2\dfrac{3}{4}=\dfrac{11}{4},~~~~4\dfrac{1}{8}=\dfrac{33}{8}.$

Now,

the number of pounds of floor that fit in $\dfrac{33}{8}$ bags is

$\dfrac{11}{4}.$

Therefore, the number of pounds of floor that fit in 1 bag is

$\dfrac{\frac{11}{4}}{\frac{33}{8}}=\dfrac{11}{4}\times\dfrac{8}{33}=\dfrac{2}{3}.$

Thus, the required number of pounds of floor that fits in each bag is $\dfrac{2}{3}.$

Answer 2

Algebraic Equations are equations that are made up of unknown variables. These variables can be represented by the letters of the alphabet.

The number of pounds of flour that will fit into each bag is $\frac{2}{3}$ pounds of flour.

Lets's represent the equal number of pounds of flour as: p

Kiran divides the flower into equal-sized bags, he fills $4\frac{1}{8}$ bags. This statement can be represented by the equation:

$4\frac{1}{8}$ bags x p = $2\frac{3}{4}$ pounds of flour

$4\frac{1}{8}$ p =$2\frac{3}{4}$

Convert mixed fractions into improper fractions

$\frac{33}{8}$ p = $\frac{11}{4}$

Divide both sides by $\frac{33}{8}$

$\frac{33}{8}$ p ÷ $\frac{33}{8}$ = $\frac{11}{4}$ ÷$\frac{33}{8}$

p = $\frac{11}{4}$ ÷$\frac{33}{8}$

p = $\frac{11}{4}$ x  $\frac{8}{33}$

p = $\frac{2}{3}$

Therefore, $\frac{2}{3}$  pounds will fit into each bag.

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