How do high-energy electrons from glycolysis and the Krebs cycle contribute to the formation of ATP from ADP in the electron transport chain? A. High-energy electrons interact with pyruvic acid to create a phosphate bond with ADP, forming ATP. B. High-energy electrons supply the needed energy to synthesize ATP from the lower-energy ADP in the electron transport chain. C. High-energy electrons supply a negative charge which causes the citric acid to oxidize, forming a phosphate group to bond with ADP. D. High-energy electrons increase the temperature of ADP so it easily reacts to form ATP.

The high energy molecules like FADH2 and NADH molecules provides electron and causes oxidative phosphorylation to generate more high-energy ATP molecules

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kasliwalalvi24 kasliwalalvi24 · Answer 2 · 2021-10-16T12:01:13+02:00

Oxidative phosphorylation is the process in which transfer of high-energy electrons to oxygen through a series of electron carriers contribute in the formation of ATP. The correct option is:

Option C. High-energy electrons supply a negative charge which causes the citric acid to oxidize, forming a phosphate group to bond with ADP.

Oxidative phosphorylation is the process in which ATP is formed as a result of the transfer of electrons from NADH and FADH2. These high-energy molecules provide electrons to oxygen molecules by a sequence of electron carriers. This transfer of electrons causes oxidative phosphorylation and yields more high-energy ATP molecules.

Some of the features of oxidative phosphorylation are:

It is composed of an electron transport chain and chemiosmosis.
In ETC, the electrons are transferred through a series of electron carriers to generate energy.
It is the main mechanism through which large amounts of ATP are yielded.

Therefore, the oxidative phosphorylation is the process of forming ATP molecules by the transfer of electrons between high-energy molecules like NADH.

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