ANSWER
[tex] \boxed {( \frac{1}{2} , 1)}[/tex]
EXPLANATION
The given parallelogram has vertices,
L(0,-3), M(-2,1), N(1,5), O(3,1).
The diagonals of the parallelogram bisect each other.
From the diagram, we can see that, the diagonals have coordinates L(0,-3),N(1,5)
and
M(-2,1),O(3,1).
The midpoint of any of the diagonals will give us the coordinates of intersection of the diagonals.
Recall the midpoint formula,
[tex](\frac{x_1+x_2}{2}, \frac{y_2+y_1}{2})[/tex]
Using L(0,-3),N(1,5) gives,
[tex](\frac{0+1}{2}, \frac{ - 3+5}{2})[/tex]
[tex](\frac{1}{2}, \frac{ 2}{2})[/tex]
[tex](\frac{1}{2}, 1)[/tex]
Or we could have also used,M(-2,1),O(3,1) to get,
[tex](\frac{-2+3}{2}, \frac{ 1+1}{2})[/tex]
[tex](\frac{ 1}{2}, \frac{ 2}{2})[/tex]
[tex](\frac{ 1}{2}, 1)[/tex]
The correct answer is C