Answer:
C. 0.0024 amu
Explanation:
We are given a table that shows us the atomic mass units (amu) for a proton, neutron, and deuteron. In order to solve this problem, we must add the (amu) of a proton and a neutron, and subtract it from the (amu) of a deuteron.
Solving:
[tex]\text{Original mass} = 1.0073 \, \text{amu} + 1.0086 \, \text{amu} = 2.0159 \, \text{amu}[/tex]
[tex]\\\text{Mass difference} = \text{Original mass} - \text{Final mass}\\[/tex]
[tex]2.0159 \,\text{amu} - 2.0135 \,\text{amu} =\boxed{ 0.0024 \, \text{amu}}[/tex]
Therefore, option C is correct.
