Question

Subtract 7a^4-4a^2b^2+67a 4 −4a 2 b 2 +6 from 3a^4+2ab^2+113a 4 +2ab 2 +11.

Answer 1

Answer:

$34a^{4}+12a^{2}b^{2}+5$

Step-by-step explanation:

The given equation is

$7a^{4}-4a^{2}b^{2}+67a^{4}-4a^{2}b^{2}+6$             .................(i)

we have to subtract it from

$3a^{4}+2a^{2}b^{2}+113a^{4}+2a^{2}b^{2}+11$             .................(ii)

First we will take the same terms of the equations in it and solve them

taking equation (i) and solving the similar terms

$7a^{4}-4a^{2}b^{2}+67a^{4}-4a^{2}b^{2}+6$  

= $84a^{4}-8a^{2}b^{2}+6$     .......................................(iii)

taking equation (ii) and solving similar terms

$3a^{4}+2a^{2}b^{2}+113a^{4}+2a^{2}b^{2}+11$  

=$116a^{4}+4a^{2}b^{2}+11$      ......................................(iv)

Now we have to subtract (iii) from (iv)

which will be

=$116a^{4}+4a^{2}b^{2}+11$- $(84a^{4}-8a^{2}b^{2}+6)$

= $116a^{4}+4a^{2}b^{2}+11 - 84a^{4}+8a^{2}b^{2}-6$  

adding and subtracting the similar terms will give us

= $34a^{4}+12a^{2}b^{2}+5$

this is the required answer  

Answer 2

Answer:

$42a^4+4ab^2+8ab^b^2+5$

Step-by-step explanation:

Subtract $7a^4-4a^2b^2+67a^4 -4a^2b^2 +6$ from $3a^4+2ab^2+113a^4 +2ab^2 +11$

Lets arrange the terms in order and then subtract. when we subtract we change the sign of each term in second parenthesis

$(3a^4+2ab^2+113a^4 +2ab^2 +11)-(7a^4-4a^2b^2+67a^4 -4a^2b^2 +6)$

$3a^4+2ab^2+113a^4 +2ab^2 +11-7a^4+4a^2b^2-67a^4 +4a^2b^2 -6)$

Now we combine like terms

$3a^4 -7a^4+113a^4-67a^4= 42a^4$

$2ab^2+2ab^2= 4ab^2$

$+4a^2b^2+4a^2b^2=8a^2b^2$

$11-6=5$

The final expression is

$42a^4+4ab^2+8ab^b^2+5$