Question

In the figure below , a cone is cut by a plane that passes through its vertex and it’s vertex and is perpendicular to its base. The height of the cone is 10 inches, and it’s diameter is 6 inches. What is the area of the cross section formed by the intersection

Answer 1

Answer:

The area of cross-section is $30inch^2$

Step-by-step explanation:

we are given that

a cone is cut by a plane that passes through its vertex and it’s vertex and is perpendicular to its base

So, cross -section will be right angled triangle

whose base will be along diameter of cone

so, base of triangle = diameter of cone =6 inch

base =6 inch

Height of triangle will be same as height of cone

so, height of triangle =10inch

now, we can find area

$Area=\frac{1}{2}\times 6\times 10$

$Area=30inch^2$