What is the area of a sector with a central angle of 2π7 radians and a diameter of 40.6 mm?


Use 3.14 for π and round your answer to the nearest hundredth.


Enter your answer as a decimal in the box.

Respuesta :

Answer:

184.85 square mm

Step-by-step explanation:

The area of a sector of a circle is [tex]\frac{1}{2} r^{2} \theta[/tex], where r is the radius and [tex]\theta[/tex] is the angle in radians subtended by the arc at the centre of the circle.

Since, diameter = 40.6 mm

So, radius(r)=20.3 mm and  [tex]\theta[/tex]=[tex]\frac{2 \pi}{7}[/tex] radians

So, area of sector= [tex]\frac{1}{2} r^{2} \theta[/tex]

=[tex]\frac{1}{2} (20.3)^2 (\frac{2 \times 3.14}{7})[/tex]

=184.85 square mm