Question

the velocity of a car changes from 60 meters per second north to 45 meters per second north in 5.0 seconds. The magnitude of the car's acceleration is

Answer 1

Acceleration is slower, so it's going to be negative:

a=Δv/Δt=(v-v₀)/t=(60-45)/5.0=15/5.0=3 m/s²

Answer 2

Answer:

Acceleration of the car is 3 m/s^2

Explanation:

Given that,

Initial speed of the car, u = 60 m/s (towards north)

Final speed of the car, v = 45 m/s (towards north)

Time taken, t = 5 s

To find :

The magnitude of the acceleration of the car.

Solve :

Let a is the acceleration of the car. It is equal to the rate of change of velocity. Its formula is given by :

$a=\dfrac{v-u}{t}$

$a=\dfrac{(45-60)\ m/s}{5\ s}$

$a=-3\ m/s^2$

$|a|=3\ m/s^2$

Negative sign shows the car is decelerating.

Therefore, the magnitude of the car's acceleration is 3 m/s^2.