could the triangle be classified as a right triangle?
![could the triangle be classified as a right triangle class=](https://us-static.z-dn.net/files/daa/eb3aa8daae7cfa12b6a328850f302796.jpg)
as you recall from the pythagorean theorem, which applies only to right-triangles, c² = a² + b².
so, a = 6, b = 8, c = 9...... if that triangle is indeed a right triangle, then 9² = 6² + 8², let's check if that's true.
[tex]\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{9}\\ a=\stackrel{adjacent}{6}\\ b=\stackrel{opposite}{8}\\ \end{cases} \\\\\\ 9=\sqrt{6^2+8^2}\implies 9=\sqrt{36+64}\implies 9=\sqrt{100}\implies 9\ne 10~~\bigotimes~~nope[/tex]