Question

Find the 35th term in the arithmetic sequence 3, 9, 15, 21, …​

Answer 1

Answer:

208

Step-by-step explanation:

First term = a = 4

Common difference = d = a2 - a1 = 9 - 3 = 6

35th term = a + (35 - 1)d

4 + (35 - 1)6

4 + (34)6

4 + 204

208

Answer 2

Answer:

207

Step-by-step explanation:

An=A1+(n-1)×R

A35=3+(35-1)×(9-3)

A35=3+34×6

A35=3+204

A35=207