Question

Find the 9th term of an arithmetic sequence that has a 4th term of 27 and a 5th term of 19

Answer 1

Answer:

-13

Step-by-step explanation:

5th term - 4th term = common difference

= 19 - 27

= -8

Thus the 9th term =   5th term +  4(-8)

=  19 - 32

= -13  (answer