Answer:
[tex]\text{Required function is} f(x)=-\log_6(x+1)[/tex]
Step-by-step explanation:
We need to find the function using given condition.
Parent function of log is log x
[tex]f(x)=\log x[/tex]
A natural logarithmic function crossing the y axis at zero and going through the point 5, -1. The asymptote is x = -1
Asymptote is x=-1
So, graph will shift 1 unit right.
[tex]f(x)=a\log_b(x+1)[/tex]
Passing point: (0,0) and (5,-1)
Using these two point we will get a and b
For point (5,-1)
[tex]-1=a\log_b(5+1)[/tex]
[tex]-1=a\log_b6[/tex]
Log to exponent change property
[tex]b^{-1/a}=6[/tex]
We will rearrange the expression
[tex]b^{-1/a}=6^{-1/-1}[/tex]
Now we compare both side to get a and b
So, a=-1 and b=6
Final function we get
[tex]f(x)=-\log_6(x+1)[/tex]
Thus, Required function is [tex]f(x)=-\log_6(x+1)[/tex]