Part 1)
here we know that supply took 10 s to reach the ground
so here we will have
[tex]y = \frac{1}{2}gt^2[/tex]
[tex]y = \frac{1}{2}\times 9.8 \times 10^2[/tex]
[tex]y = \frac{1}{2}\times 9.8 \times 100[/tex]
[tex]y = 490 m[/tex]
Part 2)
Here all the supply covered horizontal distance of 650 m in 10 s interval of time
so here we can say
[tex]speed = \frac{distance}{time}[/tex]
[tex]v = \frac{650}{10}[/tex]
[tex]v = 65 m/s[/tex]