Question

Consider the following reversible reaction

What is the equilibrium constant expression for the given system?

Answer 1

Writing Equilibrium Constant Expressions Involving Solids and Liquids. The equilibrium constant expression is the ratio of the concentrations of a reaction at equilibrium. Each equilibrium constant expression has a constant valueknown as K, the equilibrium constant.

Answer 2

Answer: $K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}$

Explanation:

$2H_2O(g)\leftrightharpoons 2H_2(g)+O_2(g)$

An equilibrium reaction is one in which rate of forward reaction is equal to the rate of backward reaction.

Equilibrium constant is defined as the ratio of the product of the concentration of products to the product of the concentration of reactants each raised to their stochiometric coefficient.

Thus $K_{eq}=\frac{[H_2]^2[O_2]}{[H_2O]^2}$