Look at the picture.
The point-slope form:
[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-3, -3) and (2, 0). Substitute:
[tex]m=\dfrac{0-(-3)}{2-(-3)}=\dfrac{3}{5}\\\\y-0=\dfrac{3}{5}(x-2)\qquad|\text{use distributive property}\\\\y=\dfrac{3}{5}x-\dfrac{6}{5}\qquad|\cdot5\\\\5y=3x-6\qquad|-5y\\\\0=3x-5y-6\qquad|+6\\\\3x-5y=6[/tex]
Answer:
point-slope form: [tex]y=\dfrac{3}{5}(x-2)[/tex]
slope-intercept form: [tex]y=\dfrac{3}{5}x-\dfrac{6}{5}[/tex]
standard form: [tex]3x-5y=6[/tex]
