What you have here is a quadratic polynomial.
The form is: ax^2 + bx + c
C is ALWAYS the y-intercept in non-linear polynomials. So we immediately know the y-intercept to be 1.
For the X-intercept(s), we can solve in a few ways, but let's use the quadratic formula.
The quadratic formula states that y=-b+-((sqrt(b^2-4ac) / 2a).
A = 2
B = 3
C = 1
Plug in your information,
[tex]\frac{-3 \frac{+}{-} \sqrt{3^2 - 4(2)(1)} }{2(2)} \\\sqrt{9 - 8}\\ \sqrt{1} \\\\\frac{-3 \frac{+}{-} 1}{4}[/tex]
y = (-3 +- 1) / 4
X = -.05
X = -1
Y = 1
X-Intercepts: -.05, -1
Y-Intercepts: 1