Question

11-Determine the specific heat of a material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C. *
I ONLY HAVE 10 MINS PLS

Answer 1

Answer:

$c=0.4\ J/g^{\circ} C$

Step-by-step explanation:

Given that,

Mass of a sample, m = 12 g

Heat absobed by the sample, Q = 96 J

It was heated from 20°C to 40°C.

We need to find the specific heat of a material. The heat absorbed by a sample is given by :

$Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{96}{12\times (40-20)}\\\\=0.4\ J/g^{\circ} C$

So, the specific heat of the material is $0.4\ J/g^{\circ} C$.

Answer 2

The specific heat of the 12-gram material when temperature changes from 20°C to 40°C is 400 joule per kg K.

What is thermodynamics?

It is a branch of science that deals with heat and work transfer.

The specific heat of material if a 12-g sample absorbed 96 J as it was heated from 20°C to 40°C.

The specific heat is given as

$Q = mc \Delta T$

where

m = mass

c = heat capacity

ΔT = change in temperature

Q = heat

Then we have

$c = \dfrac{Q}{m \Delta T}\\\\c = \dfrac{96}{12\times 10^{-3} \times (40-20)}\\\\c = \dfrac{8\times 10^3}{20}\\\\c = 400\ \ \rm \dfrac{J}{kg \ K}$

More about the thermodynamics link is given below.

https://brainly.com/question/7206767