The factors of the trinomial x² - 9x + 20 are (x-5)(x-4).
How do find the factors of a quadratic expression?
If the given quadratic expression is of the form ax²+bx+c, then its factored form is obtained by two numbers alpha(α) and beta(β) such that:
[tex]b = \alpha + \beta \\ ac =\alpha \times \beta[/tex]
Then writing b in terms of alpha and beta would help us get common factors out.
Sometimes, it is not possible to find factors easily, so using the quadratic equation formula can help out without any trial and error.
The trinomial can be factorized as,
x² - 9x + 20
= x² - 5x - 4x + 20
= x(x-5)-4(x-5)
= (x-5)(x-4)
Hence, the factors of the trinomial x² - 9x + 20 are (x-5)(x-4).
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