Question

Which chemical name is correctly paired with the chemical formula?
tin(IV) bromide, SnBr4
potassium chloride, K2Cl2
iron(II) oxide, Fe2O3
aluminum fluorate, AlF3

Answer 1

Tin bromide is correct, because the is indeed SnBr4

Potassium chloride is incorrect, because the correct formula is KCl

Iron oxide is incorrect, because the correct formula is FeO

Aluminium fluorate is incorrect, because the formula is Al(FO3)3

Hope it helped,

BioTeacher101

Answer 2

Answer : The correct option is,  tin(IV) bromide, $SnBr_4$

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) tin(IV) bromide

Tin(IV) bromide is an ionic compound because tin element is a metal and bromide element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on tin is (+4) and the the charge on bromide is (-1). Thus, the formula of the compound tin(IV) bromide will be $SnBr_4$

(b) potassium chloride

Potassium chloride is an ionic compound because potassium element is a metal and chloride element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on potassium is (+1) and the the charge on chloride is (-1). Thus, the formula of the compound potassium chloride will be $KCl$

(c) iron(II) oxide

Iron(II) oxide is an ionic compound because iron element is a metal and oxide element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on iron is (+2) and the the charge on oxide is (-2). Thus, the formula of the compound iron(II) oxide will be $FeO$

(d) aluminum fluorate

Aluminum fluorate is an ionic compound because aluminium element is a metal and fluorate element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on aluminium is (+3) and the the charge on fluorate is (-1). Thus, the formula of the compound aluminum fluorate will be $Al(FO_3)_3$

Hence, the correct option is,  tin(IV) bromide, $SnBr_4$